InLine TAE-F Duits / RJ45 8P2C kabel 0,5 m

The InLine TAE-F German to RJ45 8P2C cable (0.5 m) has a TAE-F plug on one end and an RJ45 8P2C plug on the other. It is intended for direct connection between a German TAE socket and network or telephony equipment, for example to connect Fritz!Box models such as 7170 or 7270 without using a splitter. The cable is 2-wire and comes in black.

Advantages

This 0.5 m InLine cable provides a compact, low-clutter connection with reliable contact between TAE-F and RJ45 interfaces. Its simple two-wire wiring makes it suitable for basic telephony or DSL connections where a direct TAE-to-router link is required. The standardized connectors ensure compatibility with devices that accept TAE-F and RJ45 8P2C plugs.

Suitable for

• Direct connection of Fritz!Box 7170 and 7270 to a TAE wall socket
• Connecting routers or modems to German TAE-F sockets without a splitter
• Short in-room cable runs where 0.5 m length is sufficient

Key specifications

• Connector 1: TAE-F
• Connector 2: RJ45 (8P2C)
• Wiring: 2-wire
• Length: 0.5 m
• Colour: Black
• Brand: InLine
• MPN: 18555
• EAN: 4043718187560

How to use

Plug the TAE-F connector into the German TAE wall socket and insert the RJ45 plug into the router or modem's corresponding RJ45 port. Ensure connectors are fully seated to secure proper contact. Use this cable for a single direct line; do not attempt to split the connection without appropriate splitter hardware.

Recommendations

For stable operation, keep the cable free from sharp bends and avoid placing it under heavy objects. Use the 0.5 m length for short distances only; if a longer reach is required, choose an appropriately longer cable to prevent tension on connectors.